Derivative of sinh(x)
The derivative of the hyperbolic sine is the hyperbolic cosine: $\dfrac{d}{dx}\sinh x = \cosh x$. Unlike $\sin x$, there are no sign changes when you keep differentiating.
See the derivative of sinh(x) step by step in the calculator →
📈 Graph of sinh(x) and its derivative
🔍 Why is the derivative of sinh(x) equal to $\cosh x$?
From the definition $\sinh x = \frac{e^x - e^{-x}}{2}$ and $(e^{-x})' = -e^{-x}$:
Differentiating again gives $(\cosh x)' = \sinh x$, so the derivatives alternate between sinh and cosh: the $n$-th derivative is $\sinh x$ for even $n$ and $\cosh x$ for odd $n$.
🔗 Derivative of sinh(x) with an inner function
If the argument is a function $u(x)$, the chain rule adds the inner derivative:
✏️ Worked examples
⚠️ Common mistakes
Adding a minus sign out of habit from $(\cos x)' = -\sin x$: hyperbolic derivatives of sinh and cosh have none.
Writing $(\sinh x)' = \sinh x$ – that is true for $e^x$, not for sinh.
❓ Frequently asked questions
What is the second derivative of sinh(x)?
$\sinh x$ again: $(\sinh x)'' = (\cosh x)' = \sinh x$.
Is the derivative of sinh(x) equal to cosh(x)?
Yes, $\frac{d}{dx}\sinh x = \cosh x$, with a plus sign.
What is the derivative of sinh(2x)?
$2\cosh(2x)$.