The Sum Rule: Differentiation Made Easy
The sum rule is one of the most basic and important differentiation rules. It makes differentiating functions that consist of multiple parts very simple. The principle is: Differentiate each part individually and add the results.
đ Formula of the Sum Rule
If a function $f(x)$ is the sum of two functions $u(x)$ and $v(x)$, the formula is:
Given the function:
$$ f(x) = u(x) + v(x) $$Then its derivative is:
$$ f'(x) = u'(x) + v'(x) $$đĄGood to know: The rule also applies to subtraction. In that case, it is called the difference rule: If $f(x) = u(x) - v(x)$, then the derivative is $f'(x) = u'(x) - v'(x)$.
đŞ Application in 3 Simple Steps
You can always apply the sum rule when the terms in your function are separated by a plus or minus sign.
- Identify the summands: Break the function down into its individual parts (the summands) separated by $+$ or $-$.
- Differentiate each summand individually: Apply the known differentiation rules to each part (e.g., the power rule or the derivative of constants).
- Combine the results: Add (or subtract) the individual derivatives to obtain the total derivative of the function.
âď¸ Examples for Illustration
The rule is best understood through practical examples.
Example 1: A Simple Polynomial Function
Given the function: $f(x) = x^4 + x^2$
- 1. Identify: $u(x) = x^4$ and $v(x) = x^2$.
- 2. Differentiate individually: The derivative of $u(x)$ is $u'(x) = 4x^3$. The derivative of $v(x)$ is $v'(x) = 2x$.
- 3. Combine: $f'(x) = u'(x) + v'(x) = 4x^3 + 2x$.
So the result is: $f'(x) = 4x^3 + 2x$
Example 2: Multiple Terms and Constants
Given the function: $f(x) = 2x^3 - 5x^2 + 7x - 3$
Here we differentiate each term individually:
- The derivative of $2x^3$ is $6x^2$.
- The derivative of $-5x^2$ is $-10x$.
- The derivative of $7x$ is $7$.
- The derivative of the constant $-3$ is $0$.
Combined, this gives the derivative: $f'(x) = 6x^2 - 10x + 7$
Example 3: Combination with Trigonometric Functions
Given the function: $f(x) = \sin(x) + x^3$
- 1. Identify: $u(x) = \sin(x)$ and $v(x) = x^3$.
- 2. Differentiate individually: The derivative of $u(x)$ is $u'(x) = \cos(x)$. The derivative of $v(x)$ is $v'(x) = 3x^2$.
- 3. Combine: $f'(x) = \cos(x) + 3x^2$.
So the result is: $f'(x) = \cos(x) + 3x^2$