Derivative of $\ln\left(\sin\left(x\right)\right)$
Differentiated with respect to x. Edit the function · Differentiation rules
Step-by-step solution
Input function
$$\ln\left(\sin\left(x\right)\right)$$
Start of the differentiation
$$\frac{d}{dx}{\left[\ln\left(\sin\left(x\right)\right)\right]}$$
Yellow: the expression being replaced. Green: its replacement.
Step 1 — Chain rule for the natural logarithm
Differentiation rule
📖 Rule
$$\frac{d}{dx}\big(\ln({u})\big) = \frac{u'}{{u}}$$
With:
- $u = \sin\left(x\right)$
Why: The outer derivative of the natural logarithm is the reciprocal of its argument. The chain rule adds the derivative of the argument in the numerator.
🧮 Current expression
$$\bbox[#fff1b8, padding:0.15em]{{\color{black}{\vphantom{\dfrac{d}{dx}}\,\frac{d}{dx}{\left[\ln\left(\sin\left(x\right)\right)\right]}\,}}}$$
✨ After: Chain rule for the natural logarithm
$$\bbox[#d6f5df, padding:0.15em]{{\color{black}{\vphantom{\dfrac{d}{dx}}\,\frac{\frac{d}{dx}{\left[\sin\left(x\right)\right]}}{\sin\left(x\right)}\,}}}$$
Step 2 — Derivative of Sine
Differentiation rule
📖 Rule
$$\frac{d}{dx}\sin\left(x\right)=\cos\left(x\right)$$
Why: The argument is exactly x. Apply the known elementary derivative.
Changed part:
$\frac{d}{dx}{\left[\sin\left(x\right)\right]} \;\Longrightarrow\; \cos\left(x\right)$
🧮 Current expression
$$\frac{\bbox[#fff1b8, padding:0.15em]{{\color{black}{\vphantom{\dfrac{d}{dx}}\,\frac{d}{dx}{\left[\sin\left(x\right)\right]}\,}}}}{\sin\left(x\right)}$$
✨ After: Derivative of Sine
$$\frac{\bbox[#d6f5df, padding:0.15em]{{\color{black}{\vphantom{\dfrac{d}{dx}}\,\cos\left(x\right)\,}}}}{\sin\left(x\right)}$$
Final result
$$\frac{\cos\left(x\right)}{\sin\left(x\right)}$$
Valid where:
- $\sin\left(x\right)>0$ – The logarithm argument must be positive.
The derivative is only valid where the original function is defined.
Cross-check with a computer algebra system
The derivative computed directly by the computer algebra system Maxima:
$$\frac{\cos\left(x\right)}{\sin\left(x\right)}$$
Step-by-step result ↔ Maxima: identical ✓